2p^2+p-2,72^5=0

Solution for 2p^2+p-2,72^5=0 equation:

2p^2+p-2.72^5=0

We add all the numbers together, and all the variables

2p^2+p-148.882797363=0

a = 2; b = 1; c = -148.882797363;
Δ = b2-4ac
Δ = 12-4·2·(-148.882797363)
Δ = 1192.0623789
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1192.0623789}}{2*2}=\frac{-1-\sqrt{1192.0623789}}{4}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1192.0623789}}{2*2}=\frac{-1+\sqrt{1192.0623789}}{4}
$